I am doing a review for an exam I have this week and I am stumped. Hoping someone here might have some insight:
Express your solution in set-builder notation and interval notation:
1/3(3x + 5) < 1/6(x + 4)
I have no idea what to do. Do I multiply 1/3 and 1/6 throughout the parenthesis? I feel like Id rather just get rid of the fractions because they are so messy...
Could someone please list a step by step process of how to solve these type of problems?
You are really confusing me... why are you multiplying both sides by 6?
I think you multiplied 1/3 and 1/6 through their respective equations.. but why are you now multiplying the 6 by both sides? To get rid of the fraction?
If thats the case I guess youd have...
6x + 10 < x + 4 ???
x < - 6/5 ??
hahaha wow just checked the answers and its right... so let me just make sure this is right:
step 1) distrubute the fractions through the parenthesis
step 2) multiply each side by the LCD to get rid of the fraction
step 3) get variable by itself and solve