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  1. #1
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    No Solution

    I have been working this problem out and the answer in the book is stating no solution. I am getting x=-4.

    2(x+3)-5=5x-3(1+x)
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    \displaystyle 2(x+3) - 5 = 5x - 3(1 + x)

    \displaystyle 2x + 6 - 5 = 5x - 3 - 3x

    \displaystyle 2x + 1 = 2x - 3.


    They are correct, there is not a solution - the two lines are parallel and therefore never meet...
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  3. #3
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    Quote Originally Posted by typaradise View Post
    I have been working this problem out and the answer in the book is stating no solution. I am getting x=-4.

    2(x+3)-5=5x-3(1+x)
    If x= -4, 2(-4+ 3)- 5= 2(-1)+ 5= -2+ 5= 3 but 5(-4)- 3(1+(-4))= -20- 3(-3)= -20+ 9= -11. They are not at all the same!

    Perhaps if you showed us how you got -4, we could point out a mistake.
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  4. #4
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    Quote Originally Posted by typaradise View Post
    I have been working this problem out and the answer in the book is stating no solution. I am getting x=-4.

    2(x+3)-5=5x-3(1+x)
    2x+6-5=5x-3-3x\;\;?

    2x+1=2x-3\;\;

    In algebraic terms, the question is

    "For what x is 2x+1=2x-3\;\;?"

    The answer is "no x", since 2x-2x+1\ne\ 2x-2x-3

    1\ne\ -3
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