I have been working this problem out and the answer in the book is stating no solution. I am getting x=-4. 2(x+3)-5=5x-3(1+x)
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. They are correct, there is not a solution - the two lines are parallel and therefore never meet...
Originally Posted by typaradise I have been working this problem out and the answer in the book is stating no solution. I am getting x=-4. 2(x+3)-5=5x-3(1+x) If x= -4, 2(-4+ 3)- 5= 2(-1)+ 5= -2+ 5= 3 but 5(-4)- 3(1+(-4))= -20- 3(-3)= -20+ 9= -11. They are not at all the same! Perhaps if you showed us how you got -4, we could point out a mistake.
Originally Posted by typaradise I have been working this problem out and the answer in the book is stating no solution. I am getting x=-4. 2(x+3)-5=5x-3(1+x) In algebraic terms, the question is "For what x is " The answer is "no x", since
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