# Math Help - simplification help

1. ## simplification help

What are some ways of simplifying this and why:

$(k+1)^k^+^1$

Would this be one of them?

$(k+1)(k+1)^k$

2. Originally Posted by webhound2
What are some ways of simplifying this and why:

$(k+1)^k^+^1$

Would this be one of them?

$(k+1)(k+1)^k$
I like the first form.

3. you could do something like this.


\begin{aligned}
(k+1)^{k+1}&=(k+1)(k+1)^{k} \\
&=k\cdot (k+1)^{k}+(k+1)^{k} \\
\end{aligned}

4. Originally Posted by webhound2
What are some ways of simplifying this and why:

$(k+1)^k^+^1$

Would this be one of them?

$(k+1)(k+1)^k$
If you wanted to expand it out you could use the binomial theorem

$\displaystyle (k+1)^{k+1}=\sum_{n=0}^{k+1}\binom{k+1}{n}k^n$