i am looking for some kind of infinite Series

• Feb 5th 2011, 02:30 PM
jorrigala
i am looking for some kind of infinite Series
Hi,

I do not know whether it is right place to post this thread.

I am looking for some kind of infinite sequence with following properties.
"!=" means not equal
(a+b!=c+d)
(a+a!=c+d)

i tried with fibonacci, but it did not worked
1+3=2+2
• Feb 5th 2011, 06:49 PM
CaptainBlack
Quote:

Originally Posted by jorrigala
Hi,

I do not know whether it is right place to post this thread.

I am looking for some kind of infinite sequence with following properties.
"!=" means not equal
(a+b!=c+d)
(a+a!=c+d)

i tried with fibonacci, but it did not worked
1+3=2+2

Let us assume that a,b,c,d are supposed to represent any four consecutive terms in your series. Then your last statement about the Fibonacci sequence is irrelevant as it does not represent one of the conditions you have to meet, that is 1 and 3 are not consecutive terms of the series.

Please post the exact wording of the problem.

CB
• Feb 5th 2011, 06:58 PM
jorrigala
a,b,c,d represent any number in sequence
• Feb 5th 2011, 08:27 PM
CaptainBlack
Quote:

Originally Posted by jorrigala
a,b,c,d represent any number in sequence

Again, please post the exact wording of the problem as given to you.

CB
• Feb 5th 2011, 08:29 PM
CaptainBlack
Quote:

Originally Posted by jorrigala
Hi,

I do not know whether it is right place to post this thread.

I am looking for some kind of infinite sequence with following properties.
"!=" means not equal
(a+b!=c+d)
(a+a!=c+d)

i tried with fibonacci, but it did not worked
1+3=2+2

Consider the sequence \$\displaystyle a_n=10^{10^n}\$

CB
• Mar 28th 2011, 10:08 AM
Inigo
From the information you've given, the only thing that can be ascertained is that

\$\displaystyle A {\neq} B\$

and that, therefore, you might have a series...arithmetic? Geometric? Exponential? Logarithmic? Convergent?

Indeterminate.
• Mar 28th 2011, 12:19 PM
HallsofIvy
You want a finite sequence a, b, c, d, such that \$\displaystyle a+ b\ne c+ d\$ and \$\displaystyle a+ a= 2a\ne c+ d\$? Almost any random sequence will obey that. Let's say a= 1, b= 2, c= 3, d= 4. That works, doesn't it?