Going from Standard form to Slope-Intercept form

**AbstractHero** · February 3rd 2011, 05:35 PM

First of all I'd like to say if you remember me in particular as being a jerk or an ass, I completely apologize. I was extremely confused at the time.

But anyways I think I can do this myself but I would like some reassurance. What are the steps of turning $3x + 5y = 30$ into Slope intercept form?

**skeeter** · February 3rd 2011, 05:39 PM

Originally Posted by AbstractHero

First of all I'd like to say if you remember me in particular as being a jerk or an ass, I completely apologize. I was extremely confused at the time.

But anyways I think I can do this myself but I would like some reassurance. What are the steps of turning $3x + 5y = 30$ into Slope intercept form?

the key is to isolate $y$ ...

$3x + 5y = 30$

subtract $3x$ from both sides ...

$5y = -3x + 30$

divide both sides by $5$ ...

$y = -\frac{3}{5}x + 6$

**AbstractHero** · February 3rd 2011, 06:32 PM

Thank you.

I always have a hard time figuring out what to do first. If my y is positive, should I remove what is before it? and If it is negative should I switch it around? Or what?

**pickslides** · February 3rd 2011, 06:41 PM

Consider the negative case

$3x - 5y = 30$

Same as skeeter's steps. Take 3x from both sides

$-5y = 30-3x$

Now divide -5 from both sides.

$y=\frac{3x}{5}-6$

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