# Factor Completely

• Feb 2nd 2011, 09:19 PM
alyosha2
Factor Completely
$
x^4 - y^4 = (x^2 + y^2)(x^2 - y^2)
\\ = (x^2 + y^2)(x + y)(x - y)
$

I'm ok with this until the last part. It looks like as the second term is a difference of squares it has been factored as well. I'm just a bit fuzzy on the use of brackets here. Can anyone help?

Thanks.
• Feb 2nd 2011, 09:20 PM
Prove It
Yes, each factorisation is a difference of two squares...