(1+ax)/(1+bx) = 1+(a-b)x+(b^2-ab)x^2 is this correct upto x^2 terms? thanks
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Originally Posted by BabyMilo (1+ax)/(1+bx) = 1+(a-b)x+(b^2-ab)x^2 is this correct upto x^2 terms? thanks Now we expand Hence, your initial expression will be: So yes, your expansion is correct.
It's correct! I happen to find the following method to be better than the binomial theorem:
Last edited by TheCoffeeMachine; Feb 1st 2011 at 04:07 PM.
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