(1+ax)/(1+bx)

= 1+(a-b)x+(b^2-ab)x^2

is this correct upto x^2 terms?

thanks

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- February 1st 2011, 12:20 PMBabyMiloBinomal Expansion
(1+ax)/(1+bx)

= 1+(a-b)x+(b^2-ab)x^2

is this correct upto x^2 terms?

thanks - February 1st 2011, 12:36 PMIthaka
- February 1st 2011, 01:02 PMTheCoffeeMachine
It's correct! I happen to find the following method to be better than the binomial theorem: