The distance (in miles) traveled when driving at a certain speed for hours,
then driving miles/hour faster for another hour.
Express the distance in terms of .
the distance traveled when driving at mph for hours is the expression = ?
ADDED to that distance is driving 1 hour at mph FASTER,
so the expression to be added is = ?
The final expression = ?
my second question is..
1/3y + 9 = 1/9y Solve for Y.
Thanks for any help..