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Math Help - distance problem and finding Y

  1. #1
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    distance problem and finding Y

    The distance (in miles) traveled when driving at a certain speed for hours,
    then driving miles/hour faster for another hour.
    Express the distance in terms of .

    the distance traveled when driving at mph for hours is the expression = ?

    ADDED to that distance is driving 1 hour at mph FASTER,
    so the expression to be added is = ?

    The final expression = ?


    my second question is..

    1/3y + 9 = 1/9y Solve for Y.


    Thanks for any help..
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  2. #2
    MHF Contributor harish21's Avatar
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    let the distance be X..

     X = S \frac{miles}{hour} \times 13 \;hours \;+ (S+5)\frac{miles}{hour} \times 1\; hours\; = ...

    finish...

    2nd question:

    \dfrac{1}{3y}+9 = \dfrac{1}{9y}

    \dfrac{1}{3y}-\dfrac{1}{9y}=-9

    \dfrac{1}{3y}\times\dfrac{3}{3}-\dfrac{1}{9y}=-9


    \dfrac{3}{9y}-\dfrac{1}{9y}=-9

    finish...
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