The distance (in miles) traveled when driving at a certain speed for hours,

then driving miles/hour faster for another hour.

Express the distance in terms of .

the distance traveled when driving at mph for hours is the expression = ?

ADDED to that distance is driving 1 hour at mph FASTER,

so the expression to be added is = ?

The final expression = ?

my second question is..

1/3y + 9 = 1/9y Solve for Y.

Thanks for any help..