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Math Help - two "solve for" questions

  1. #1
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    two "solve for" questions

    Alright so I have the answers to these two questions, but I still don't get how to solve them since I suck haha

    question 1) F = \frac{9}{5}C + 32 solve for "C"

    answer is C = \frac{5}{9}(F - 32)

    How does the fraction end up inverted? I get it to F - 32 = \frac{9}{5}C then I don't know what to do


    question 2) d = v.t + \frac{1}{2}at^2 solve for "a"

    answer is a = \frac{2 (d-v.t)}{t^2}

    help is very much appreciated and somewhat urgent!
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  2. #2
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    Quote Originally Posted by henryW View Post
    Alright so I have the answers to these two questions, but I still don't get how to solve them since I suck haha

    question 1) F = \frac{9}{5}C + 32 solve for "C"

    answer is C = \frac{5}{9}(F - 32)

    How does the fraction end up inverted? I get it to F - 32 = \frac{9}{5}C then I don't know what to do


    question 2) d = v.t + \frac{1}{2}at^2 solve for "a"

    answer is a = \frac{2 (d-v.t)}{t^2}

    help is very much appreciated and somewhat urgent!
    Dear henryW,

    1) F - 32 = \frac{9}{5}C

    Multiply both sides by 5 and divide both sides by 9. You will get the answer.

    2) First substract, v.t from both sides. Then multiply both sides by \frac{2}{t^2}.
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