# Thread: two "solve for" questions

1. ## two "solve for" questions

Alright so I have the answers to these two questions, but I still don't get how to solve them since I suck haha

question 1) $F = \frac{9}{5}C + 32$ solve for "C"

answer is $C = \frac{5}{9}(F - 32)$

How does the fraction end up inverted? I get it to $F - 32 = \frac{9}{5}C$ then I don't know what to do

question 2) $d = v.t + \frac{1}{2}at^2$ solve for "a"

answer is $a = \frac{2 (d-v.t)}{t^2}$

help is very much appreciated and somewhat urgent!

2. Originally Posted by henryW
Alright so I have the answers to these two questions, but I still don't get how to solve them since I suck haha

question 1) $F = \frac{9}{5}C + 32$ solve for "C"

answer is $C = \frac{5}{9}(F - 32)$

How does the fraction end up inverted? I get it to $F - 32 = \frac{9}{5}C$ then I don't know what to do

question 2) $d = v.t + \frac{1}{2}at^2$ solve for "a"

answer is $a = \frac{2 (d-v.t)}{t^2}$

help is very much appreciated and somewhat urgent!
Dear henryW,

1) $F - 32 = \frac{9}{5}C$

Multiply both sides by 5 and divide both sides by 9. You will get the answer.

2) First substract, $v.t$ from both sides. Then multiply both sides by $\frac{2}{t^2}$.