Again, to factorize; not solve..
$\displaystyle
x^(3a+2) + 3x^(2a+2) - 5x^2
$
$\displaystyle
-5x^2 + x^(3a+2) + x^(2a+2)
$
$\displaystyle
x^-0.5( -5x^(2.5) + 3^(2a+2.5) + 1^(3a+2.5))
$ *Not too sure about this step, went off-track here, i think..
Again, to factorize; not solve..
$\displaystyle
x^(3a+2) + 3x^(2a+2) - 5x^2
$
$\displaystyle
-5x^2 + x^(3a+2) + x^(2a+2)
$
$\displaystyle
x^-0.5( -5x^(2.5) + 3^(2a+2.5) + 1^(3a+2.5))
$ *Not too sure about this step, went off-track here, i think..
Hello, BobBali!
Didn't you PREVIEW your post?
You didn't see that it didn't come out clearly?
And how did you manage to factor out $\displaystyle x^{-\frac{1}{2}}$ ? . . . And why?
Like Plato, I'll guess at what you meant.
$\displaystyle \text{Factor: }\;x^{3a+2} + 3x^{2a+2} - 5x^2$
Take another look at what we have: . $\displaystyle x^{3a}\!\cdot\!x^2 + 3\!\cdot\!x^{2a}\!\cdot\!x^2 - 5\!\cdot\!x^2$
Factor out $\displaystyle x^2\!:\;\;x^2\left(x^{3a} + 3x^{2a} - 5)$
. . and that's the best we can do.