Q. If 653xy is divisible by 80 then find the value of x+y. 80 = 8 * 10 So y = 0 (As it is divisible by 10) Now 3x0 should be divisible by 8. X can be both 2 and 6. The answer is 6. As per my calculation it can be both 2 and 6. Am i right ?
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Originally Posted by vivek_master146 Q. If 653xy is divisible by 80 then find the value of x+y. 80 = 8 * 10 So y = 0 (As it is divisible by 10) Now 3x0 should be divisible by 8. X can be both 2 and 6. The answer is 6. As per my calculation it can be both 2 and 6. Am i right ? 65320 is not divisible by 80.
Originally Posted by vivek_master146 Q. If 653xy is divisible by 80 then find the value of x+y. 80 = 8 * 10 So y = 0 (As it is divisible by 10) That's correct. Now 3x0 should be divisible by 8. X can be both 2 and 6. The answer is 6. As per my calculation it can be both 2 and 6. Am i right ? If you have divided 653x0 by 10 you are left with 653x. Therefore 53x must be divisible by 8.
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