I am given this equation of an unknown base:
It has a solution of x=5 and x=8 which are likely to be in our base 10.
I tried to find out the unknown base by comparing the co-efficients of the equations by doing so:
<--in base 10
<--in unknown base
Then I try to solve for the unknown base:
1*b = 13, b=13
but...
5*1 + 2*b = 40
2b = 35
b=17.5
How can the b in the equations be different? If this is the case, what is the actual base for the equation?
thanks!
thanks CaptainBlack.
But what is the reason for adding a b this way? And why wouldn't my previous method work?
I calculated the equation and for (5b)x, b=13 but the b^2 + 2b +5, b=13.892 or -13.892. So is 13 considered the base enough though there is 0.892 more?