Is it the same as it is in Part 1? If so, and by the Remainder Theorem.
The polynomial has a remainder of 2 when divided by and a remainder of 3, when divided by . The remainder when is divided by is , i.e. can be written as
Find a and b.
Well I got this already a= 1 and b=1
but the second question I don't know what to do...
Given that is a cubic polynomial with coefficient of being 1, and −1 is a solution of the equation , find .
I'm not too sure how to start... If -1 is a solution of the question when that means must be a factor right? I don't know what to do from here...
All replies are appreciated