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Math Help - Elementary Algebra help

  1. #1
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    Elementary Algebra help

    Hi,

    My name is Kevin. I am 34 years old and I would like to enroll in College as a freshman. I'm studying to pass the placement test and Algebra is my weakest link. The school gives a sample test online with nine Algebra questions. At first I could only do one. Now I can do two or three. I would like to post two questions here that I can't figure out. I need to know what type of questions these are so that I can find more examples for practice and if you could break them down step by step that would be awesome.

    1)

    x^2 - x - 6
    __________ =
    x^2 - 4

    (This is a fraction)

    A.

    x - 3
    ________
    2

    B.

    x - 3
    _______
    x - 2

    C.

    x - 3
    ______
    x + 2

    D.

    3
    ___
    2


    2)

    (3x-2y)^2 =

    A. 9x^2 - 4y^2

    B. 9x^2 + 4y^2

    C. 9x^2 + 4y^2 - 6xy

    D. 9x^2 + 4y^2 - 12xy

    Thank you
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  2. #2
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    Quote Originally Posted by lawkev View Post
    Hi,

    My name is Kevin. I am 34 years old and I would like to enroll in College as a freshman. I'm studying to pass the placement test and Algebra is my weakest link. The school gives a sample test online with nine Algebra questions. At first I could only do one. Now I can do two or three. I would like to post two questions here that I can't figure out. I need to know what type of questions these are so that I can find more examples for practice and if you could break them down step by step that would be awesome.

    1)

    x^2 - x - 6
    __________ =
    x^2 - 4

    (This is a fraction)

    A.

    x - 3
    ________
    2

    B.

    x - 3
    _______
    x - 2

    C.

    x - 3
    ______
    x + 2

    D.

    3
    ___
    2


    2)

    (3x-2y)^2 =

    A. 9x^2 - 4y^2

    B. 9x^2 + 4y^2

    C. 9x^2 + 4y^2 - 6xy

    D. 9x^2 + 4y^2 - 12xy

    Thank you
    For the first one you have to factorise the numerator and denominator and then simplify the fraction by cancelling out the common factor.

    For the second one you have to expand: (3x - 2y)^2 = (3x - 2y)(3x - 2y) = ....
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  3. #3
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    I wish I understood but I don't.
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  4. #4
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    Quote Originally Posted by lawkev View Post
    I wish I understood but I don't.
    What don't you understand?
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  5. #5
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    What do you mean by factorise the numerator and denominator and then simplify the fraction by cancelling out the common factor?

    What does expand mean for (3x - 2y)^2 = (3x - 2y)(3x - 2y) = ....?

    I'm trying to avoid taking remedial classes but I think might have to.
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  6. #6
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    Frankly, on a placement test, you want the most accurate score, NOT the highest score. "Avoiding" taking a remedial course by answering questions you needed help on is the last thing you should do!
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  7. #7
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    Quote Originally Posted by lawkev View Post
    What do you mean by factorise the numerator and denominator and then simplify the fraction by cancelling out the common factor?

    What does expand mean for (3x - 2y)^2 = (3x - 2y)(3x - 2y) = ....?

    I'm trying to avoid taking remedial classes but I think might have to.
    If you were told to factorise the following:

    (a) x^2 - x - 6

    (b) x^2 - 4

    would you know what to do and how to do it?

    (Do you know what the words 'numerator' and 'denominator' mean?)

    Do you know that (3x - 2y)^2 means (3x - 2y)(3x - 2y)? If you were told to expand (3x - 2y)(3x - 2y) would you know what to do and how to do it?
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  8. #8
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    "If you were told to factorise the following:

    (a) x^2 - x - 6

    (b) x^2 - 4

    would you know what to do and how to do it?"

    No, I would not.

    "Do you know what the words 'numerator' and 'denominator' mean?"

    Yes, I do.

    "Do you know that (3x - 2y)^2 means (3x - 2y)(3x - 2y)?"

    Yes

    "If you were told to expand (3x - 2y)(3x - 2y) would you know what to do and how to do it?"

    No


    I started studying from the Khan Academy website. I need a lot of help and I should get it there.

    Thank You
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