Results 1 to 2 of 2

Math Help - Find # of digirs using log

  1. #1
    Newbie
    Joined
    Apr 2009
    Posts
    16

    Find # of digirs using log

    I got a question to solve. Find the number of digits in 6^{100}
    Value of \log_{10} 2 =  0.30102 \and \log_{10} 3 =  0.47712 \was \given
    I used logarithm.

    \log y = 100log(2*3)
    log y = 100 (log2 + log3)
    log y = 100( 0.30102 + 0.47712)
    logy = 100 * 0.77814
    logy = 77.814

    So will the number of digits will be 78 ? because whatever power 10 is raised to. the number of digits is (power + 1). Am i correct. If not then what should be the answer.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Dec 2007
    From
    Ottawa, Canada
    Posts
    3,110
    Thanks
    68
    78 it is.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 8
    Last Post: March 22nd 2011, 04:57 PM
  2. Replies: 2
    Last Post: July 5th 2010, 08:48 PM
  3. Replies: 1
    Last Post: February 17th 2010, 03:58 PM
  4. Replies: 0
    Last Post: June 16th 2009, 12:43 PM
  5. Replies: 2
    Last Post: April 6th 2009, 08:57 PM

Search Tags


/mathhelpforum @mathhelpforum