# Thread: Help with simultaneous equation

1. ## Help with simultaneous equation

2y-3x=2 & 4y2-4xy=18x2=5

2. Originally Posted by jimbo28
2y-3x=2 & 4y2-4xy=18x2=5
It is not very clear. Did you mean?:

$\displaystyle \begin{Bmatrix} 2y-3x=2\\4y^2-4xy-18x^2=5\end{matrix}$

Fernando Revilla

3. Yes apart from 2y - 3x = 2. Thankyou ever so much if you can help me.

Kind regards

4. Originally Posted by jimbo28
Yes apart from 2y - 3x = 2. Thankyou ever so much if you can help me.
All right, I've corrected it. Then from the first equation:

$\displaystyle y=\dfrac{2+3x}{2}$

Now, substitute $\displaystyle y$ in the second one and you'll obtain a quadratic equation on $\displaystyle x$ .

Fernando Revilla

5. Thankyou Fernando, any chance I can have the answers with working outs?

6. Originally Posted by jimbo28
Thankyou Fernando, any chance I can have the answers with working outs?

What have you tried? The next stage is to substitute $\displaystyle y=\dfrac{2+3x}{2}$ into the second equation.

7. Here is a suggestion.
Note that $\displaystyle 2y=3x+2$.
Write the other equation as $\displaystyle (2y)^2-2x(2y)-18x^2=5$.
Now substitute for $\displaystyle (2y)$.

8. Originally Posted by jimbo28
Thankyou Fernando, any chance I can have the answers with working outs?