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Math Help - Need Solution Guidance for Quadratic Inequalities and Regions of y ≥ √(9-x^2)≥≤

  1. #1
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    Question Need Solution Guidance for Quadratic Inequalities and Regions of y ≥ √(9-x^2)≥≤

    thanks for helping

    please be very detailed--- and, THANK YOU!
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  2. #2
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    The corresponding equation is y=\sqrt{9-x^2} which is the upper half of the circle x^2+y^2=9 (make sure you understand the algebra here).

    See if you can finish it on your own now.
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