# Need Solution Guidance for Quadratic Inequalities and Regions of y ≥ √(9-x^2)≥≤

• Jan 22nd 2011, 04:54 AM
Farah
Need Solution Guidance for Quadratic Inequalities and Regions of y ≥ √(9-x^2)≥≤
(Bow) thanks for helping (Bow)

please be very detailed--- and, THANK YOU!(Itwasntme)
• Jan 22nd 2011, 05:14 AM
DrSteve
The corresponding equation is $y=\sqrt{9-x^2}$ which is the upper half of the circle $x^2+y^2=9$ (make sure you understand the algebra here).

See if you can finish it on your own now.