(Bow) thanks for helping (Bow)

please be very detailed--- and, THANK YOU!(Itwasntme)

- Jan 22nd 2011, 03:54 AMFarahNeed Solution Guidance for Quadratic Inequalities and Regions of y ≥ √(9-x^2)≥≤
(Bow) thanks for helping (Bow)

please be very detailed--- and, THANK YOU!(Itwasntme) - Jan 22nd 2011, 04:14 AMDrSteve
The corresponding equation is $\displaystyle y=\sqrt{9-x^2}$ which is the upper half of the circle $\displaystyle x^2+y^2=9$ (make sure you understand the algebra here).

See if you can finish it on your own now.