Hey, I have an exam tomorrow afternoon and I have a quick question I'd like to clear up. In the following example:

$\displaystyle \log{(2x-2)}-\log{(x^2-1)}

=\log{2(x+1)}, x>1

$

Why is the restriction x>1? In all the previous examples in the book, they show x>0 as you cannot log negatives. But in this example, they show x>1. I figure x cannot equal 1, but why cannot it be 0<x<1?