equation: x^2-6x+1=5

Complete the square

x^2-6x=4
then i took have of 6 which is 3 and squared it to come up with 9

this is what I have now:

x^2-6x+9=4+9

$a(x-\frac{b}{2a})^{2}+\underbrace{c-\frac{b^{2}}{4a}}_{\text{constant}}$