- So! I think
so
When
My answers page says the co-ords are as in and
Putting x as -3 in Gives
SO to me x = -3 and y = 2. But the answers page says other wise, who's right?
I've already had 1 answer wrong in this book!
The way you solved above tired ME out!
Try keeping it simpler (so your teacher will not give up!), like:
x^2 + 4x + 5 = 3x + 11
x^2 + 4x - 3x + 5 - 11 = 0
x^2 + x - 6 = 0
(x + 3)(x - 2) = 0
x = -3 or x = 2
Now, using y = 3x + 11 :
when x = -3, y = 3(-3) + 11 = 2
when x = 2, y = 3(2) + 11 = 17
Now you and/or your book can rant and rave, but the (x,y) solutions are:
(-3,2) and (2,17) ; over and out
This is incorrect. "If ab= 0 then either a= 0 or b= 0". You have (x- 3)(x+ 2)= 0 so either x- 3= 0 or x+ 2= 0. Then x= 3 or x= -2, not "x= 2 or -3"
As I said before, x= -2 or x= 3. If x= -2, then y= 3(-2)+ 11= 5. If x= 3, y= 3(3)+ 11= 20. the correct solutions are (-2, 5) and (3, 20).so
When
My answers page says the co-ords are as in and
Did you check your answers by putting them back into the equations?Putting x as -3 in Gives
SO to me x = -3 and y = 2. But the answers page says other wise, who's right?
I've already had 1 answer wrong in this book!
You've just wrecked every hope I had, I understood it until you posted that. It's the format mess the post is in that's throwing me off.
So X could equal either 3 or -2. I actually wrote that down wrong and continued from my error (I even wrote it down wrong when typing this up!). I am prone to writing things down wrong ! And failing the maths due to negligence.
After de-cyphering the format of your post it all makes sense.
Very helpful.
Cheers, that was pretty a pretty serious error.
Edit: You can see I checked, you corrected it.