$\displaystyle y=3x+11$

$\displaystyle y=x^2+4x+5$

- $\displaystyle 3x+11=x^2+4x+5$
- $\displaystyle 11=x^2+x+5$
- $\displaystyle 6=x^2+x$
- $\displaystyle x^2+x-6=0$
- $\displaystyle (x-3)(x+2)$
- So! I think $\displaystyle x = 2 or -3$

so

When $\displaystyle x=2$

$\displaystyle y=6+11$

$\displaystyle y=17$

$\displaystyle x=-3$

$\displaystyle y=-9+11$

$\displaystyle y=2

$

My answers page says the co-ords are $\displaystyle (2,-3)$ as in $\displaystyle x =2$ and $\displaystyle y = -3$

Putting x as -3 in $\displaystyle y=x^2+4x+5$ Gives $\displaystyle y=9-12+5 = 2$

SO to me x = -3 and y = 2. But the answers page says other wise, who's right?

I've already had 1 answer wrong in this book!