I kinda need help with this. x^2 + 3x+ 2 ax^2 - 9ax + 18a
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Originally Posted by lovestarwarz I kinda need help with this. x^2 + 3x+ 2 ax^2 - 9ax + 18a $\displaystyle (x\pm\alpha)(x\pm\beta)$ $\displaystyle \alpha\cdot\beta=2$ $\displaystyle \alpha +\beta=3$
For the second, take out a common factor of $\displaystyle \displaystyle a$ first, then use the method dwsmith suggested.
Originally Posted by lovestarwarz x^2 + 3x+ 2 is (x+a)(x+b) where a+b=3 and ab=2 Originally Posted by lovestarwarz ax^2 - 9ax + 18a Same goes here, just factor out 'a' first.
Mmk (:
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