If $\displaystyle a+4b+9c+16d=1$ $\displaystyle 4a+9b+16c+25d=12$ $\displaystyle 9a+16b+25c+36d=123$ Then find $\displaystyle 16a+25b+36c+49d = $
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Originally Posted by jacks If $\displaystyle a+4b+9c+16d=1$ $\displaystyle 4a+9b+16c+25d=12$ $\displaystyle 9a+16b+25c+36d=123$ Then find $\displaystyle 16a+25b+36c+49d = $ $\displaystyle 3\left(9a+16b+25c+36d\right)-3\left(4a+9b+16c+25d\right)+\left(a+4b+9c+16d\righ t)=\;\;?$
Of course, you understand that when we say "Thank You", we really mean "Blast, Archie Mead got there before me!"
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