Originally Posted by

**kensington** **QUESTION:** Suppose that r and s are distinct real solutions of the quadratic equation ax^2 + bx + c = 0. In terms of a,b,c, obtain forumlas for r + s and rs.

**SOLUTION?**

so what i know the answer is r+s= -b/a and rs=c/a but im confused as to why.

SO i started this...

suppose r=x and s=y:

(x+y)= M ( where M is an element of the real #)

(xy)=T (where M is an element of the real #)

so then x(M-x)=T

x^2-Mx+T=0

ax^2-aMx+aT=0

assuming aM =b and aT=c we get out original quadratic equation.

Now im stuck.. i tried solving for r+s(aMx) using what i have but i get something different. Please help =/