Originally Posted by
kensington QUESTION: Suppose that r and s are distinct real solutions of the quadratic equation ax^2 + bx + c = 0. In terms of a,b,c, obtain forumlas for r + s and rs.
SOLUTION?
so what i know the answer is r+s= -b/a and rs=c/a but im confused as to why.
SO i started this...
suppose r=x and s=y:
(x+y)= M ( where M is an element of the real #)
(xy)=T (where M is an element of the real #)
so then x(M-x)=T
x^2-Mx+T=0
ax^2-aMx+aT=0
assuming aM =b and aT=c we get out original quadratic equation.
Now im stuck.. i tried solving for r+s(aMx) using what i have but i get something different. Please help =/