Here's the problem:
7e^(-2t) - 5e^(-5t) + 4e^(-6t) = 0
Solve for t.
I've tried to solve it a few ways (taking the natural log) but each leads to a dead end.
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Then you tell us...
I factored out a but that didn't seem to help.
I am left with :
Originally Posted by jut I factored out a but that didn't seem to help. I am left with : Well as , this reduces to: putting gives: which by Descartes rule of signs we know has exactly one positive root, which is what we want if we are looking for a real solution to the original equation. RonL
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