Are you serious?
You have just done quadratic equations in one of your other post.. Follow the same procedure..
$\displaystyle \boxed{7x^2-22x+3=0}$ is a quadratic equation!! Follow the same procedure as you did in THIS POST OF YOURS
Substitution is the only way to solve this because you have different powers of x
You can solve that quadratic to give two values of x:
$\displaystyle 7x^2-22x+3 = (7x-1)(x-3) = 0$
Using those two values of x plug into equation 1 to find their corresponding y values (you will get two pairs of solutions as a final answer)
edit: an example
you know that x = 3 is one of the roots and so you can sub x=3 into eq1 to find y: $\displaystyle y = 3(3) - 11 = -2$
Hence $\displaystyle (3, -2)$ is one pair of solutions. Can you do the same thing for the other root?