Results 1 to 5 of 5

Math Help - simplify

  1. #1
    Junior Member
    Joined
    Dec 2010
    Posts
    52

    simplify

    (^16)log(sqrt8)= 0.5* (^16)log(8) = more ?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    -1
    e^(i*pi)'s Avatar
    Joined
    Feb 2009
    From
    West Midlands, England
    Posts
    3,053
    Thanks
    1
    What does (^16) represent? The base of the log?

    I suspect you're meant to make use of the fact that 16 = 2^4 and 8 = 2^3
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jan 2011
    Posts
    2
    Please, confirm which (if any) is the initial expresion you would like to simplify:

    x^{16}\times \log\sqrt{8}

    or

    16^{ \log\sqrt{8}}

    or

     \log_{16}\sqrt{8}
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member
    Joined
    Dec 2010
    Posts
    52
    i meant this one \log_{16}\sqrt{8}
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,831
    Thanks
    1602
    So you're asking can you simplify \displaystyle \log_{16}{\sqrt{8}} = \frac{1}{2}\log_{16}{8} any further?

    \displaystyle \frac{1}{2}\log_{16}{8} = \frac{1}{2}\log_{16}{(2\cdot 4)}

    \displaystyle = \frac{1}{2}\log_{16}{2} + \frac{1}{2}\log_{16}{4}

    \displaystyle = \frac{1}{2}\log_{16}{(16^{\frac{1}{4}})} + \frac{1}{2}\log_{16}{(16^{\frac{1}{2}})}

    \displaystyle = \frac{1}{8}\log_{16}{16} + \frac{1}{4}\log_{16}{16}

    \displaystyle = \frac{1}{8} + \frac{1}{4}

    \displaystyle = \frac{3}{8}.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. simplify #2
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: September 21st 2009, 03:37 PM
  2. Please simplify
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: April 27th 2009, 05:32 AM
  3. Can you simplify this further?
    Posted in the Algebra Forum
    Replies: 4
    Last Post: April 23rd 2009, 07:45 AM
  4. Simplify
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 12th 2009, 06:06 AM

Search Tags


/mathhelpforum @mathhelpforum