I'm not sure where you got that...
Can someone please help me out with these question's. I'm trying to add, subtract, multiply and divide functions.
How will I do that for:
f (x) = x^2 - 3 g (x) = 2 - square root (x+1)
Basically the way i did it was.
Add: x^2 - 3 + 2 - square root of (x+1)
= x^2 - square root of (x+1) - 1
Subtract: x^2 - 3 - 2 + square root (x+1)
= x^2 + square root (x+1) - 5
Multiply: I'm not sure how to do this one ... but i got:
f (x) . g (x) = (x^2-3) (2- square root (x+1)
= 2x^2 - square root (x+1)^3 - (square root (x+1)^3 + 3 square root (x+1)
but it's probably wrong.
Can someone help me with these, thanks.
Divide: i'll figure it out after i know how to multiply
Actually for the 3rd part: multiplication I got:
(x^2-3) X (2- square root (x+1)
= 2x^2 - square root (x+1)^3 - 6 + 3 square root (x+1)
= square root (x+1)^3 + 2x^2 + 3 square root (x+1) - 6
Thanks I think I sort of get it. Did I do the adding/subtracting right?
Thanks, I made an error when I tried to multiply it... I havne't doen math in a while and forget a lot of the more simpler stuff... I understand all the basics of rational functions but I find it harder when adding this stuff up sometimes. If I had gotten:
2x^2 - x^2 square root (x+1) - 6 + x^2 square root (x+1)
how would I add it then? I made those numbers up.... but how would i add x^2 quare root (x+1) with x^2 square root (x+1) ... would it just become x^4 square root (x+1) ?
and if i had x^2 square root (x+1) + x^3 square root (x+1) ... would i still add the two to become x^5 (square root x+1) or do i leave it since hte exponenets are different?
thanks.
It's okay, and it's good that you want to go through them again!
One way for you to be sure, you can introduce something else.2x^2 - x^2 square root (x+1) - 6 + x^2 square root (x+1)
how would I add it then? I made those numbers up.... but how would i add x^2 quare root (x+1) with x^2 square root (x+1) ... would it just become x^4 square root (x+1) ?
Let
Then
How would you deal with this? It's simple like that, right?
and if i had x^2 square root (x+1) + x^3 square root (x+1) ... would i still add the two to become x^5 (square root x+1) or do i leave it since hte exponenets are different?
No no. I see that you are confusing something.
it cannot be further simplified (other than by factoring giving
When you multiply something with the same base (x) but different powers, then you add. If it's division, you subtract.
Here what you can do is only factor and simplify:
Ok, I might not reply for a while now; I'm going to bed. See you tomorrow!