LetA=-2 -1 -3 6 1

1 1 1 -2 1

2 3 1 -2 4

Find a basis for the column space Col(A) ofA, and a basis for the null space

Nul(A) ofA.

Show that foranymatrixA, ifuandvare in the null space ofA, then

so isu+v.

I know that I have to get the matrix into echelon form inorder to find the pivot points, but when I tried doing this I kept getting different answers when I did it two different ways. It would be really helpful if someone could show me the steps do doing this