A airplane that travels from one city to another city against the wind takes it 4 hours to get there, the voyage back only takes it 2 hours. If the distance between both city's is 600km, what is the speed of the plane?
So far I have:
D = V x T
Go 600 4
Return 600 2
It's a table.
So,
600/4=V
600/2=V
Is this right so far?
Okay, so the net speed going (against the wind) was 600/4= 150 mph and returning (with the wind) was 600/2= 300 mph. Taking v to be "indicated air speed" (speed of the plane relative to the wind) and w to be the wind speed, we have v- w= 150 and v+ w= 300. Add those two equations to solve for v and subtract them to solve for w.