Originally Posted by

**Hellbent** Hi,

If $\displaystyle j, k,$ and $\displaystyle n$ are consecutive integers such that $\displaystyle 0 < j < k < n$ and the units digit of the product $\displaystyle jn$ is $\displaystyle 9$, what is the units digit of $\displaystyle k$?

A. 0

B. 1

C. 2

D. 3

E. 4

I guessed E once but my final answer is C.

The question is a bit unclear to me. j, k and n are consecutive such that 0 < j < k < n; so 0 < 1 < 2 < 3, but j times n gives me 1 x 3 = 3 and not 9 as the problem states.