I'm having a tough time understanding these:
X^6 - 1
And if you can, please give me a little explanation on how you got the answer.
I'm having a tough time understanding these:
X^6 - 1
And if you can, please give me a little explanation on how you got the answer.
Once you've used the difference of two squares (as Pickslides suggests) then you can use the sum/difference of two cubes
$\displaystyle (a \pm b)^3 = (a \pm b)(a^2 \mp ab + b^2)$
Since x^6 and 1 are both square numbers and cube numbers you can start with either formula
$\displaystyle \displaystyle\frac{5\sqrt{16}\sqrt{3}+\sqrt{25}\sq rt{3}}{5\sqrt{3}}\Rightarrow \left(\frac{\sqrt{3}}{\sqrt{3}}\right)\left(\frac{ 5\sqrt{16}+\sqrt{25}}{5}\right)\Rightarrow\frac{5\ sqrt{16}+5}{5}\Rightarrow\left(\frac{5}{5}\right)( \sqrt{16}+1)=4+1=5$
It should probably really be $\displaystyle \pm 5$ but you may only need the positive solution.