hi i need to know how to factorise this: i know if it was 2x^2 - 121 it would = (x+11) (x-11) so for this one would it be (2x +11) (2x-11) ??? if not could you please tell me where im going wrong! Thanks!
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Originally Posted by andyboy179 hi i need to know how to factorise this: i know if it was 2x^2 - 121 it would = (x+11) (x-11) so for this one would it be (2x +11) (2x-11) ??? if not could you please tell me where im going wrong! Thanks! if it is x^2 - 121 = (x -11)(x + 11 ) but 2x^2 - 121 is not equal to (x- 11)(x+11) ur solution for the question is rite 4x^2 - 121 = (2x - 11)(2x +11)
In general, [tex]a^2- b^2= (a- b)(a+ b)/[tex] Actually, , not . I presume that was a mis-type. so, yes, .
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