Thread: factorise, hard

hi i need to know how to factorise this:



i know if it was 2x^2 - 121 it would = (x+11) (x-11)
so for this one would it be (2x +11) (2x-11) ???

if not could you please tell me where im going wrong!

Thanks!

Originally Posted by andyboy179

hi i need to know how to factorise this:



i know if it was 2x^2 - 121 it would = (x+11) (x-11)
so for this one would it be (2x +11) (2x-11) ???

if not could you please tell me where im going wrong!

Thanks!

if it is x^2 - 121 = (x -11)(x + 11 )
but 2x^2 - 121 is not equal to (x- 11)(x+11)

ur solution for the question is rite 4x^2 - 121 = (2x - 11)(2x +11)

In general, [tex]a^2- b^2= (a- b)(a+ b)/[tex]

Actually, , not . I presume that was a mis-type.

so, yes, .