hi i need to know how to factorise this:
Attachment 20407
i know if it was 2x^2 - 121 it would = (x+11) (x-11)
so for this one would it be (2x +11) (2x-11) ???
if not could you please tell me where im going wrong!
Thanks!
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hi i need to know how to factorise this:
Attachment 20407
i know if it was 2x^2 - 121 it would = (x+11) (x-11)
so for this one would it be (2x +11) (2x-11) ???
if not could you please tell me where im going wrong!
Thanks!
if it is x^2 - 121 = (x -11)(x + 11 )Quote:
Originally Posted by andyboy179
but 2x^2 - 121 is not equal to (x- 11)(x+11)
ur solution for the question is rite 4x^2 - 121 = (2x - 11)(2x +11)
In general, [tex]a^2- b^2= (a- b)(a+ b)/[tex]
Actually,, not
. I presume that was a mis-type.
so, yes,
.
