Math Help - Negative fraction exponents

1. Negative fraction exponents

Just wondering if this is the case:

$\displaystyle 3^\frac{m}{n}=\frac{m}{3^n}$

The exponent in the first term should be negative but i don't know how to do that in latex sorry!

Thanks

BIOS

2. $3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}$

click on the formula to see the latex.

3. Originally Posted by BIOS
Just wondering if this is the case:

$\displaystyle 3^\frac{m}{n}=\frac{m}{3^n}$

The exponent in the first term should be negative but i don't know how to do that in latex sorry!

Thanks

BIOS
$\displaystyle\frac{m}{3^n}=m\left(\frac{1}{3^n}\ri ght)=m\left(\frac{3^0}{3^n}\right)=m\left(3^{0-n}\right)=m3^{-n}$

4. Thanks alot for the replies and the clarification.

So is this the case:

$3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}=\frac{1}{\sqrt [n]{3^m}}$

5. Originally Posted by BIOS
Thanks alot for the replies and the clarification.

So is this the case:

$3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}=\frac{1}{\sqrt [n]{3^m}}$
Yup.

6. Sweet. Thanks again for the help. I have most of the rules down now. Just need to work on my logarithms!