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Math Help - Negative fraction exponents

  1. #1
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    Negative fraction exponents

    Just wondering if this is the case:

    \displaystyle 3^\frac{m}{n}=\frac{m}{3^n}

    The exponent in the first term should be negative but i don't know how to do that in latex sorry!

    Thanks

    BIOS
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  2. #2
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    3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}

    click on the formula to see the latex.
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  3. #3
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    Quote Originally Posted by BIOS View Post
    Just wondering if this is the case:

    \displaystyle 3^\frac{m}{n}=\frac{m}{3^n}

    The exponent in the first term should be negative but i don't know how to do that in latex sorry!

    Thanks

    BIOS
    \displaystyle\frac{m}{3^n}=m\left(\frac{1}{3^n}\ri  ght)=m\left(\frac{3^0}{3^n}\right)=m\left(3^{0-n}\right)=m3^{-n}
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  4. #4
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    Thanks alot for the replies and the clarification.

    So is this the case:

    3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}=\frac{1}{\sqrt [n]{3^m}}
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  5. #5
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    Quote Originally Posted by BIOS View Post
    Thanks alot for the replies and the clarification.

    So is this the case:

    3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}=\frac{1}{\sqrt [n]{3^m}}
    Yup.
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  6. #6
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    Sweet. Thanks again for the help. I have most of the rules down now. Just need to work on my logarithms!
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