Just wondering if this is the case:

$\displaystyle \displaystyle 3^\frac{m}{n}=\frac{m}{3^n}$

The exponent in the first term should be negative but i don't know how to do that in latex sorry!

Thanks

BIOS

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- Jan 7th 2011, 12:58 PMBIOSNegative fraction exponents
Just wondering if this is the case:

$\displaystyle \displaystyle 3^\frac{m}{n}=\frac{m}{3^n}$

The exponent in the first term should be negative but i don't know how to do that in latex sorry!

Thanks

BIOS - Jan 7th 2011, 01:00 PMsnowtea
$\displaystyle 3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}$

click on the formula to see the latex. - Jan 7th 2011, 01:11 PMArchie Meade
- Jan 7th 2011, 02:02 PMBIOS
Thanks alot for the replies and the clarification.

So is this the case:

$\displaystyle 3^{-\frac{m}{n}} = \frac{1}{3^{\frac{m}{n}}}=\frac{1}{\sqrt [n]{3^m}}$ - Jan 7th 2011, 02:03 PMsnowtea
- Jan 7th 2011, 02:07 PMBIOS
Sweet. Thanks again for the help. I have most of the rules down now. Just need to work on my logarithms!