# Thread: Algebra problems

1. ## Algebra problems

I have 3 problems I need help with. I am completely clueless but more than willing to learn. I also don't know how to insert some of the symbols so I wrote it out, I hope it's not to confusing

1. x(not equal to sign)0, then 1-1
x

2. a(not equal to) 0, a(not equal to)1; ax-b then b=
a-b

3. k= 1 mb(squared), then b=
2

Thank You !!

Edit: For some reason when I submitted the post some of the numbers that were supposed to go underneath the underline moved to the left.

1. x is supposed to go under 1-1
2. a-b is supposed to go under ax-b
3. 2 is supposed to under the 1 as to say half

2. 1. $\dfrac{1-1}{x} \ ,\ x \neq 0$ Unless I'm missing something very obvious this is 0.

2. $\dfrac{ax-b}{a-b}$ it needs to be equal to something to manipulate it. I will say it's equal to y for argument's sake

$y = \dfrac{ax-b}{a-b}$ then $y(a-b) = ax-b$ and $ya-yb = ax-b$.

Collect the b terms on one side and factor.

3. $\frac{1}{2}mb^2$. Again it needs to equal to something.

Once more assuming it's equal to y then multiplying through by 2/m gives $\dfrac{2y}{m} = b^2$

3. Your post is really hard to read (perhaps a lot of spaces were ignored).
You may want to read the latex tutorial in the Latex Help subforum for future posts.

As an example type:
[tex] x \neq \frac{y^2 + 1}{z + a} [/ math]
(without space after the /)
to get
$x \neq \frac{y^2 + 1}{z + a}$

4. Originally Posted by e^(i*pi)
1. $\dfrac{1-1}{x} \ ,\ x \neq 0$ Unless I'm missing something very obvious this is 0.

2. $\dfrac{ax-b}{a-b}$ it needs to be equal to something to manipulate it. I will say it's equal to y for argument's sake

$y = \dfrac{ax-b}{a-b}$ then $y(a-b) = ax-b$ and $ya-yb = ax-b$.

Collect the b terms on one side and factor.

3. $\frac{1}{2}mb^2$. Again it needs to equal to something.

Once more assuming it's equal to y then multiplying through by 2/m gives $\dfrac{2y}{m} = b^2$
Thank you so much for your help! I also said the same thing for #1 that it IS 0 but the problem as was given to me clearly states x is not equal to 0. So clearly I was confused.

Also for #2 and #3 in order to find b which is what the original problems are asking me to do, you basically are isolating and getting b by itself correct?

Again thanks so much.

5. Originally Posted by snowtea
Your post is really hard to read (perhaps a lot of spaces were ignored).
You may want to read the latex tutorial in the Latex Help subforum for future posts.

As an example type:
[tex] x \neq \frac{y^2 + 1}{z + a} [/ math]
(without space after the /)
to get
$x \neq \frac{y^2 + 1}{z + a}$
I'm so sorry about that snowtea, I was not trying to make the post hard to read. I will take your advice and read up on that.

Thanks!

6. Originally Posted by eagertolearn
Thank you so much for your help! I also said the same thing for #1 that it IS 0 but the problem as was given to me clearly states x is not equal to 0. So clearly I was confused.

Also for #2 and #3 in order to find b which is what the original problems are asking me to do, you basically are isolating and getting b by itself correct?

Again thanks so much.
For 2 and 3 you have an expression rather than an equation because you've not told us what the formulae are equal to. You can't get b on it's own because there is nothing on the other side of the equals sign to manipulate

For formatting, if you can't use latex then at least use plain text:

(ax-b)/(a-b) is question 2 for example