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Math Help - Algebra problems

  1. #1
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    Algebra problems

    I have 3 problems I need help with. I am completely clueless but more than willing to learn. I also don't know how to insert some of the symbols so I wrote it out, I hope it's not to confusing



    1. x(not equal to sign)0, then 1-1
    x




    2. a(not equal to) 0, a(not equal to)1; ax-b then b=
    a-b





    3. k= 1 mb(squared), then b=
    2



    Thank You !!

    Edit: For some reason when I submitted the post some of the numbers that were supposed to go underneath the underline moved to the left.

    1. x is supposed to go under 1-1
    2. a-b is supposed to go under ax-b
    3. 2 is supposed to under the 1 as to say half
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  2. #2
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    e^(i*pi)'s Avatar
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    1. \dfrac{1-1}{x} \ ,\ x \neq 0 Unless I'm missing something very obvious this is 0.

    2. \dfrac{ax-b}{a-b} it needs to be equal to something to manipulate it. I will say it's equal to y for argument's sake

    y = \dfrac{ax-b}{a-b} then y(a-b) = ax-b and ya-yb = ax-b.

    Collect the b terms on one side and factor.

    3. \frac{1}{2}mb^2. Again it needs to equal to something.

    Once more assuming it's equal to y then multiplying through by 2/m gives \dfrac{2y}{m} = b^2
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  3. #3
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    Your post is really hard to read (perhaps a lot of spaces were ignored).
    You may want to read the latex tutorial in the Latex Help subforum for future posts.

    As an example type:
    [tex] x \neq \frac{y^2 + 1}{z + a} [/ math]
    (without space after the /)
    to get
    x \neq \frac{y^2 + 1}{z + a}
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  4. #4
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    Quote Originally Posted by e^(i*pi) View Post
    1. \dfrac{1-1}{x} \ ,\ x \neq 0 Unless I'm missing something very obvious this is 0.

    2. \dfrac{ax-b}{a-b} it needs to be equal to something to manipulate it. I will say it's equal to y for argument's sake

    y = \dfrac{ax-b}{a-b} then y(a-b) = ax-b and ya-yb = ax-b.

    Collect the b terms on one side and factor.

    3. \frac{1}{2}mb^2. Again it needs to equal to something.

    Once more assuming it's equal to y then multiplying through by 2/m gives \dfrac{2y}{m} = b^2
    Thank you so much for your help! I also said the same thing for #1 that it IS 0 but the problem as was given to me clearly states x is not equal to 0. So clearly I was confused.

    Also for #2 and #3 in order to find b which is what the original problems are asking me to do, you basically are isolating and getting b by itself correct?

    Again thanks so much.
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  5. #5
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    Quote Originally Posted by snowtea View Post
    Your post is really hard to read (perhaps a lot of spaces were ignored).
    You may want to read the latex tutorial in the Latex Help subforum for future posts.

    As an example type:
    [tex] x \neq \frac{y^2 + 1}{z + a} [/ math]
    (without space after the /)
    to get
    x \neq \frac{y^2 + 1}{z + a}
    I'm so sorry about that snowtea, I was not trying to make the post hard to read. I will take your advice and read up on that.

    Thanks!
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  6. #6
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by eagertolearn View Post
    Thank you so much for your help! I also said the same thing for #1 that it IS 0 but the problem as was given to me clearly states x is not equal to 0. So clearly I was confused.

    Also for #2 and #3 in order to find b which is what the original problems are asking me to do, you basically are isolating and getting b by itself correct?

    Again thanks so much.
    For 2 and 3 you have an expression rather than an equation because you've not told us what the formulae are equal to. You can't get b on it's own because there is nothing on the other side of the equals sign to manipulate


    For formatting, if you can't use latex then at least use plain text:

    (ax-b)/(a-b) is question 2 for example
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