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Math Help - Circle graphs

  1. #1
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    Circle graphs

    I have a basic understanding of circular graphs but I don't know how to do this question

    Find the equation of the circle whose centre lies on the line y = 4 and which passes through the points (2, 0) and (6, 0).
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  2. #2
    MHF Contributor alexmahone's Avatar
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    Quote Originally Posted by jgv115 View Post
    I have a basic understanding of circular graphs but I don't know how to do this question

    Find the equation of the circle whose centre lies on the line y = 4 and which passes through the points (2, 0) and (6, 0).
    The centre of a circle lies on the perpendicular bisector of any 2 points on its circumference. The perpendicular bisector of (2, 0) and (6, 0) is the line x = 4. But we also know that the centre lies on the line y = 4. So, the centre of the circle is (4, 4).

    Can you proceed?
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  3. #3
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    Recall the standard form for the equation of a circle:

    (x-h)^2+(y-k)^2=r^2

    where (h,k) is the center of the circle and r is the radius of the circle.

    Now use the information from Alex's post.
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