In correcting this number: "0.39" to 3 d.p and 3 s.f, would it be as follows?
3 d.p --> 0.390
3 s.f --> 0.390
Thanks.
Yes, you are correct.
For any further questions on significant digits, try this website:
Significant Figures
But, even that the last zero can be ommited after the decimal place, we are asked here for 3 s.f, which means there should be three numbers.
For example, what is the solution for this question:
Correct 0.0004298 to 3 s.f? When you solve it you will know what I mean.
Thanks.
Yes, because the number of "significant digits" tells you the accuracy of the measurement. 0.39 means that, measured to the nearest hundreth, the number is 0.39- that is that the true value is somewhere between 0.385 and 0.395. 0.390 means that it was measured to thousandths place- the true value is between 0.3995 and 0.3905.
0.0004298 to 3 significant figures is 0.000430 or, better, $\displaystyle 4.30 \times 10^{-4}$. The fact that it has 3 significant figures means it is accurate to between 0.0004295 and 0.0004305.For example, what is the solution for this question:
Correct 0.0004298 to 3 s.f? When you solve it you will know what I mean.
Thanks.