Percentages

**Revxx** · January 3rd 2011, 06:22 AM

If in a survey 33% of people preffered somethnig and 67% didnt, then one more person voted changing this result to 25% preffered and 75% not preffered (the one person making 8% difference) how many people wouldve voted? any help would be appreciated

**alexmahone** · January 3rd 2011, 06:59 AM

Let the number of people initially be x.

$\frac{0.33x}{0.67x+1}=\frac{25}{75}$

Can you proceed?

**Revxx** · January 3rd 2011, 07:09 AM

im still not sure how many people it would have been

**e^(i*pi)** · January 3rd 2011, 07:14 AM

In post 2 alexmahone has used x to denote the number of people.

If you solve that equation for x then you will work out the number of people it would have been

**alexmahone** · January 3rd 2011, 07:16 AM

I think the 33% and 67% are merely approximations to $\frac{1}{3}$ and $\frac{2}{3}$ .

$\frac{\frac{x}{3}}{\frac{2}{3}x+1}=\frac{25}{75}=\ frac{1}{3}$

$x=\frac{2}{3}x+1$

$\frac{x}{3}=1$

$x=3$

**Revxx** · January 3rd 2011, 07:26 AM

so it would have been 1 person for and 3 against? or 1 and 2 then 1 and 3? ( the person that made it 25% and 75% and voted agaisnt)

**alexmahone** · January 3rd 2011, 07:31 AM

Originally Posted by Revxx

so it would have been 1 person for and 3 against? or 1 and 2 then 1 and 3? ( the person that made it 25% and 75% and voted agaisnt)

First, 1 against 2. Later, 1 against 3.

**Revxx** · January 3rd 2011, 07:45 AM

thankyou very much for your help

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