I'm not sure how to begin attacking this one.

Given the equation

use the Quadratic Formula to solve for

(a) x in terms of y (b) y in terms of x.

Can I get a hint?

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- July 10th 2007, 02:33 PMearacheflOne more equation
I'm not sure how to begin attacking this one.

Given the equation

use the Quadratic Formula to solve for

(a) x in terms of y (b) y in terms of x.

Can I get a hint? - July 10th 2007, 03:08 PMThePerfectHacker
- July 10th 2007, 03:27 PMearachefl
Hmm...

I get that I need to somehow isolate the variables on one side of the equation. I just can't seem to figure out how. It seems like every way I attack it, x and y stay mixed up together.

Are you saying to take

and and group them together somehow? - July 10th 2007, 03:34 PMJonboy
He's saying identify a b and c.

Remember a quadratic is in the form - July 10th 2007, 03:44 PMearachefl
That was my first guess as to what he meant, and I did plug those numbers (-1, -4, 1) into the Quadratic Formula, and got the answer . However, this is nowhere near close to the book's answers of

or

so I'm no closer in understanding.

Am I supposed to plug the output of the Quadratic Formula in wherever y appears? - July 10th 2007, 10:55 PMJhevon
- July 11th 2007, 06:39 AMearachefl
Thanks to all for the hints. My textbook hasn't given any example of this kind of problem, but just dumped the question in our laps regardless.

- July 11th 2007, 08:22 PMJhevon