log(34+10x)=2log(x+5) this is what I have done so far: log(34+10x)=log(x+5)^2 log(34+10x)=logx^2+10x+25 Now I am stuck
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Originally Posted by getnaphd log(34+10x)=2log(x+5) this is what I have done so far: log(34+10x)=log(x+5)^2 log(34+10x)=logx^2+10x+25 Now I am stuck just drop the logs now. you have log of something equals log of something, it means the somethings must be equal so, 34 + 10x = (x + 5)^2 and solve for x
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