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Math Help - logarithms

  1. #1
    Junior Member
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    logarithms

    log(34+10x)=2log(x+5)

    this is what I have done so far:

    log(34+10x)=log(x+5)^2

    log(34+10x)=logx^2+10x+25

    Now I am stuck
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by getnaphd View Post
    log(34+10x)=2log(x+5)

    this is what I have done so far:

    log(34+10x)=log(x+5)^2

    log(34+10x)=logx^2+10x+25

    Now I am stuck
    just drop the logs now. you have log of something equals log of something, it means the somethings must be equal

    so, 34 + 10x = (x + 5)^2

    and solve for x
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