A housewife buys a certain amount of beef at £4 per kilo and the same amount of sausages at £3 per kilo. If she had split the money she spent equally between the beef and sausages she would have got 2 kilos more. How much did she spend

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- Jan 19th 2006, 12:24 PMbonbhoyToo thick to solve this problem!!!!
A housewife buys a certain amount of beef at £4 per kilo and the same amount of sausages at £3 per kilo. If she had split the money she spent equally between the beef and sausages she would have got 2 kilos more. How much did she spend

- Jan 19th 2006, 01:06 PMThePerfectHackerQuote:

Originally Posted by**bonbhoy**

$\displaystyle \frac{x}{3}-\frac{x}{4}=2$

To solve this you need to find the common denominator. Which is 12, and multiply both sides by 12:

$\displaystyle 12\frac{x}{3}-12\frac{x}{4}=12\times 2$

thus,

$\displaystyle 4x-3x=24$

thus,

$\displaystyle x=24kg$

Thus, she brought 24 kilos for both of them. Thus, a total of 48 kilograms of meat where brough. - Jan 19th 2006, 02:14 PMCaptainBlackQuote:

Originally Posted by**bonbhoy**

Then:

$\displaystyle 4x+3x=s$

Now if instead $\displaystyle s/2$ is spent on beef and also on sausage these

buy $\displaystyle (s/2)/4\ kg$ of beef and $\displaystyle (s/2)/3\ kg$ of sausage. As the sum

of these is $\displaystyle 2\ kg$ more than previously we have:

$\displaystyle s/8+s/6 = 2x+2$,

but $\displaystyle s=7x$ so:

$\displaystyle \frac{7x}{8}+\frac{7x}{6}=2x+2$,

which has solution $\displaystyle x=48\ kg$, or $\displaystyle s= 336$pounds

These numbers seem implausibly large given the scenario.

RonL