For we have:
so, for :
Fernando Revilla
Hi
Facing a problem with sketching this modulus graph.
To get the equations of the lines I have to draw, I have labeled them as i, ii and iii.
However, after I checked it with my graphing calculator, I realised that the graph for part ii has a positive gradient. Circled the error I faced in my attachment in red.
Only one example was given in my text to help me solve this question. The tutorials and videos on sketching modulus graphs online only showed how to sketch one modulus function.
Please help me to check my approach and tell me where I went wrong.
Thanks in advance.
For we have:
so, for :
Fernando Revilla
Hello, dd86!
Fernando found your error . . .
(ii) Consider .
. . . . . . . .
becomes:. .
. . . . . . . .
. . . . . . . .
The graph looks like this:
Code:| | (1,4) | * | * | * * | * | * * - - - - - - - + - - - - - - * - - |* * | * | * | * * | * | * * | * | * | (-1,-6)| |