Printable View
So I was just doing a calculus question and on the solutions ..
it jumps from
then it skips to
and I don't know how that works.. there have been a number of questions that have done that and now I think its time i asked about it. Of course, thats not the simplest form but I understand how it simplifies from there.. I just don't get how it skips from the first one to the second.
If someone could care to explain I'd really love it thanks :D
Are you sure it's not?
If it is, they've realised there's a common factor ofin the numerator.
sorry yeah i'll fix it my bad!
I still don't get it though.. could you explain in more depth?
.
Do you see that there is a common factor of
Yeah I see it but why is it that there are 5 of them in the first equation and only 3 in the 2nd one?
ab+ ac= a(b+ c) has, in your sense, "two" a's on the left and only one on the right!
6+ 10= 2(3)+ 2(5)= 2(3+ 5) has two "2"s on the left and only one on the right. They are not supposed to be the same!
I guess that makes sense.. still don't completely understand though D:
Hello, Klutz!
Quote:
![\dfrac{3(x+2)^2(x^2+1)-2x(x+2)^3}{(x^2+1)^2} \;=\;\dfrac{(x+2)^2\bigg[3(x^2+1)-2x(x+2)\bigg]}{(x^2+1)^2}](http://latex.codecogs.com/png.latex?\dfrac{3(x+2)^2(x^2+1)-2x(x+2)^3}{(x^2+1)^2} \;=\;\dfrac{(x+2)^2\bigg[3(x^2+1)-2x(x+2)\bigg]}{(x^2+1)^2})
Examine the numerator: .
The two terms have a common factor: .
. . . . . . . . . . . . . . . . . . . . . . . . . . . . .
Factor it out: .
ahh! I got it thanks so much. Gosh I'm so slow.