Can someone please help me out with this problem? The diagonals of a rectangle ABCD intersect at O. If angle BOC=70 degree, find angle ODA. Thanks.....
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Have you drawn the rectangle with the diagonals? You are going to have an isosceles triangle. ODA = 90 - OBC
Last edited by dwsmith; Dec 18th 2010 at 06:07 PM.
Angle AOD= BOC ("vertical angles" theorem). Triangle AOD is an isosceles triangle so its base angles are the same and, of course, the angles in a triangle add to 180 degrees.
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