I have a question here that I have only partially worked.

Question:

3c+4y+z=7

2y+z=3

-5+3y+8z=-31

Working:

Z=3-2y, given because 2y+z=3.

so

My calculations break down here, where I try to solve the third equation for x...

I can't seem to finish the operation.

Here is the attempted working:

[Math]-5c+3y+8z=37 \rightarrow -5+3(2-\frac{3}{2}x)+8z=-31 \rightarrow -5x+6-\frac{9}{2}x+8z=-31 \rightarrow 9\frac{1}{2}C+6+8z=-31[/tex]so

This is the point at which my calculations fall apart.

Thank you!