How would do I get: $\displaystyle u^2+v^2 = \frac{1}{4}$ From: $\displaystyle (\frac{u}{u^2+v^2})^2 + (\frac{-v}{u^2+v^2})^2 = 4 $ Can't seem to get there. Thanks
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$\displaystyle (\frac{u}{u^2+v^2})^2 + (\frac{-v}{u^2+v^2})^2 = \frac{u^2}{(u^2+v^2)^2} + \frac{v^2}{(u^2+v^2)^2} = \frac{u^2 + v^2}{(u^2+v^2)^2} = \frac{1}{u^2+v^2} $
ahh, good one. Thanks
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