The width of a rectangle is 2 m less than the length. The area is 8 m^2. Find the length and the width.
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Hi june bug, let x= lenght then width = x-2 Area = 8 x(x-2) =8 x^2 -2x -8 = 0 Factor the quadratic and solve for x bjh
so would the width be -2 and the length be 4? i used the equation x^2-2x-8=0 and solved using the quadratic formula and that's what i got.
you scrap the -2 and use only the 4 and then what is the width ? bjh
2, correct? thank you so much!
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